There are fifty marbles in a

sack: red, blue and green.
There are ten more green
than blue marbles in the
sack. The probability of
drawing a red or blue marble
is one-half. Write and solve
an equation to determine
how many of each color
marble is in the sack

"The probability of

drawing a red or blue marble
is one-half."
Means that Red+Blue=half * 50 = 25.

Can you do the rest?

i don't know if i can do it...

Known facts:

Red+Blue+Green=50
Red+Blue=25
Green-Blue=10

Can you juggle a little with the above equations to come up with the answer?

so there be 25 green, 15 blue, 10 red???

Correct, good job!

To solve this problem, we can set up an equation using the given information.

Let's assume the number of blue marbles in the sack is "x". Since there are ten more green marbles than blue marbles, the number of green marbles would be "x + 10".

Given that the total number of marbles in the sack is fifty, we can write the equation as:

x + (x + 10) + (red marbles) = 50

Since the probability of drawing a red or blue marble is one-half, we know that the sum of red and blue marbles should be half of the total number of marbles:

red marbles + (x + blue marbles) = 50/2 = 25

Now, we can solve this system of equations to find the values of x (blue marbles) and red marbles.

x + (x + 10) + red marbles = 50 ---(1)
red marbles + (x + blue marbles) = 25 ---(2)

Simplifying equation (1):
2x + 10 + red marbles = 50
2x + red marbles = 40

Simplifying equation (2):
red marbles + x + blue marbles = 25
red marbles + 2x + 10 = 25
red marbles + 2x = 15

Now, we have a system of two equations:
2x + red marbles = 40
red marbles + 2x = 15

We can solve this system of equations by substitution or elimination method.

By using substitution method, we can isolate one of the variables in terms of the other. Let's isolate red marbles in terms of x from equation (1):
red marbles = 40 - 2x

Substituting this value in equation (2):
40 - 2x + 2x = 15
40 = 15

This equation is not possible. Therefore, there is no solution that satisfies the given conditions of the problem.

Hence, there is no way to determine how many of each color marble is in the sack, based on the given information and the probability constraint.