Posted by candy on Monday, March 28, 2011 at 3:15pm.
0.3g of clotrimazole (C22H17ClN2) was dissolved in 80ml of anhydrous acetic acid. This was titrated with 0.1M perchloric acid using 0.3ml of naphtholbenzein as indicator until the colour changes from brownish-yellow to green.
1ml of 0.1M perchloric acid is equivalent to 34.48mg of clotrimazole (C22H17ClN2).
1st titration= A ml of 0.1M perchloric acid was used.
2nd titration= B ml of 0.1M perchloric acid was used.
Is a blank titration required?
A blank titration is not required in this experiment because a blank solution is used as a reference point for zero concentration of the analyte. In this case, the analyte is clotrimazole. Since clotrimazole was dissolved in the anhydrous acetic acid, which serves as the solvent, there is no need for a blank titration.
To determine if a blank titration is required, we first need to understand what a blank titration is.
A blank titration is a control experiment that involves running the same titration procedure without the analyte (in this case, clotrimazole) present. It is done to account for any background color changes or other factors that may affect the accuracy of the titration results.
In this scenario, since the question does not specify whether a blank titration was conducted, we cannot determine if it is required or not. Typically, a blank titration is performed when there is a concern about background color changes or other interferences. If such concerns exist or if it is mentioned in the experiment setup, a blank titration should be performed.
Without additional information, it is not possible to determine with certainty whether a blank titration should be conducted. It would be best to consult the specific experimental procedure or guidelines to determine if a blank titration is necessary in this case.