the perimeters of 2 similar polygons are 20 and 28. One side of the smaller polygons is 4. What is the congruent side of the larger polygon?

it doesn't solve anything at all... so,it not useful to me..

umm...thanks.

To find the congruent side of the larger polygon, we need to use the concept of similarity. Similar polygons have corresponding sides that are proportional to each other.

Let's set up a proportion to find the ratio between the perimeters of the smaller and larger polygons:

Ratio of perimeters = Perimeter of smaller polygon / Perimeter of larger polygon

Given that the perimeters are 20 and 28 respectively, we can write:

Ratio of perimeters = 20 / 28

Simplifying this ratio gives us:

Ratio of perimeters = 5 / 7

Now, we can use this ratio to find the length of the congruent side of the larger polygon:

Congruent side of larger polygon = Ratio of perimeters * Length of side of smaller polygon

Given that one side of the smaller polygon is 4, we can plug in the values:

Congruent side of larger polygon = (5 / 7) * 4

Simplifying this expression:

Congruent side of larger polygon = 20 / 7

Therefore, the congruent side of the larger polygon is approximately 2.857 units long.

This is quite simple.

Use ratios to get 20:28
(smaller polygon:larger polygon)
Which equals 4:7.
This means that any side lengths of the smaller polygon to the ratio of its congruent side lengths of the larger polygon equals 4:7.
The work is cut out for you, as we know that one side is 4, therefore the other is 7.