If 3.00 mol of calcium carbonate is heated to produce calcium oxide and carbon dioxide, how many grams of calcium oxide are produced?
see your post above.
To find the number of grams of calcium oxide produced, we need to use the molar ratios of calcium carbonate and calcium oxide.
First, let's write the balanced chemical equation for the reaction:
CaCO3 -> CaO + CO2
From the equation, we can see that 1 mole of calcium carbonate (CaCO3) produces 1 mole of calcium oxide (CaO).
Given that we have 3.00 moles of calcium carbonate, we can conclude that we will also have 3.00 moles of calcium oxide.
To convert from moles to grams, we need to use the molar mass of calcium oxide (CaO). The molar mass of calcium (Ca) is 40.08 g/mol, and the molar mass of oxygen (O) is 16.00 g/mol.
Therefore, the molar mass of calcium oxide (CaO) is:
40.08 g/mol (Ca) + 16.00 g/mol (O) = 56.08 g/mol (CaO)
Now, to find the mass of calcium oxide (CaO), we can use the following equation:
mass (g) = moles x molar mass
mass(CaO) = 3.00 mol x 56.08 g/mol ≈ 168.24 grams
Therefore, approximately 168.24 grams of calcium oxide are produced when 3.00 moles of calcium carbonate are heated.