what is the chage in volume when the length of the shipping box increases from 5 feet to 6 feet?
To calculate the change in volume when the length of the shipping box increases from 5 feet to 6 feet, you need to understand the formula for calculating the volume of a rectangular prism.
The volume (V) of a rectangular prism can be calculated by multiplying the length (L) by the width (W) and the height (H):
V = L * W * H
In this case, you are given that the initial length is 5 feet and the final length is 6 feet. However, the problem does not provide the values of the width and height. So, to find the change in volume, we need to make an assumption or provide the missing information.
If we assume that the width and height of the box remain the same, we can calculate the initial and final volumes and then find the difference.
Let's assume the width (W) and height (H) of the box are constant:
Initial Volume (V1) = L1 * W * H = 5 ft * W * H
Final Volume (V2) = L2 * W * H = 6 ft * W * H
The change in volume (ΔV) can be calculated by subtracting the initial volume from the final volume:
ΔV = V2 - V1 = (6 ft * W * H) - (5 ft * W * H)
= W * H * (6 ft - 5 ft)
= W * H * 1 ft
Therefore, the change in volume when the length of the shipping box increases from 5 feet to 6 feet is given by the expression W * H * 1 ft, where W and H represent the width and height of the box, respectively.