Write net ionic equation for all the reactions that occurred with the metals.
Cu(s) with Ag+
Pb(s) with Cu2+(aq)
thank you
http://www.files.chem.vt.edu/RVGS/ACT/notes/activity_series.html
Any metal will displace the ion of another metal BELOW it in the activity series.
Cu(s) + 2Ag^+ ==> 2Ag(s) + Cu^+2
To write the net ionic equation for these reactions, we need to first write the balanced chemical equation for each reaction, and then identify the spectator ions to derive the net ionic equation.
1. Reaction: Cu(s) with Ag+(aq)
The balanced chemical equation for this reaction is:
Cu(s) + 2Ag+(aq) → Cu2+(aq) + 2Ag(s)
To find the spectator ions, we look at the ions that remain unchanged on both sides of the equation. In this case, the spectator ion is 2Ag+(aq).
The net ionic equation for this reaction is:
Cu(s) + 2Ag+(aq) → Cu2+(aq) + 2Ag(s)
2. Reaction: Pb(s) with Cu2+(aq)
The balanced chemical equation for this reaction is:
Pb(s) + Cu2+(aq) → Pb2+(aq) + Cu(s)
To find the spectator ions, we look at the ions that remain unchanged on both sides of the equation. In this case, the spectator ion is Cu2+(aq).
The net ionic equation for this reaction is:
Pb(s) + Cu2+(aq) → Pb2+(aq) + Cu(s)
Therefore, the net ionic equation for the reactions described is:
Cu(s) + 2Ag+(aq) → Cu2+(aq) + 2Ag(s)
Pb(s) + Cu2+(aq) → Pb2+(aq) + Cu(s)