how many moles of nitrate ions are in 10.00 grams of copper(II) nitrate?".
How many moles are in 10.00 g Cu(NO3)2?
That is moles = grams/molar mass
Then there are 2 nitrate ions per molecule of Cu(NO3)2 so nitrate ions must be just twice that.
To determine the number of moles of nitrate ions in 10.00 grams of copper(II) nitrate, we need to follow these steps:
1. Identify the chemical formula of copper(II) nitrate. Copper(II) nitrate is written as Cu(NO3)2 since it consists of one copper ion (Cu2+) and two nitrate ions (NO3-).
2. Calculate the molar mass of copper(II) nitrate. To do this, we need to find the atomic masses of copper (Cu), nitrogen (N), and oxygen (O) from the periodic table. The atomic mass of copper is approximately 63.55 g/mol, nitrogen is around 14.01 g/mol, and oxygen is roughly 16.00 g/mol. Summing up these values, we get:
Molar mass of Cu(NO3)2 = (63.55 g/mol) + 2 * [(14.01 g/mol) + 3 * (16.00 g/mol)]
3. Calculate the number of moles of copper(II) nitrate. To do this, divide the given mass (10.00 grams) by the molar mass of Cu(NO3)2 obtained in step 2. This will give us the number of moles of copper(II) nitrate.
Number of moles = mass / molar mass
4. Finally, determine the number of moles of nitrate ions. Since there are two nitrate ions (NO3-) in one molecule of Cu(NO3)2, multiply the number of moles obtained in step 3 by 2.
Number of moles of nitrate ions = number of moles of Cu(NO3)2 * 2
By following these steps, you can calculate the quantity of nitrate ions in a given mass of copper(II) nitrate.