A cat chases a mouse across a 1.0 m high table. the mouse steps out og the way, and the cat slides off the table and strikes the floor 2.2 m from the edge of the table. When the cat slid off the table, what was it's speed?
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To find the cat's speed when it slid off the table, we can analyze the situation using the principles of kinematics.
Given:
Height of the table (h) = 1.0 m
Horizontal distance traveled by the cat (d) = 2.2 m
To determine the cat's speed, we need to find its horizontal component of velocity. We can use the equation of motion:
v² = u² + 2as
Where:
v = final velocity
u = initial velocity (which is zero since the cat was at rest)
a = acceleration (due to gravity, approximately 9.8 m/s²)
s = vertical distance traveled (height of the table)
Since the cat slid off the table perpendicular to our frame of reference, the vertical distance traveled is equal to the height of the table. Therefore, s = h.
Now, we can plug the values into the equation and solve for v:
v² = 0² + 2 * 9.8 * 1.0
v² = 19.6
v ≈ √19.6
v ≈ 4.43 m/s
So, the cat's speed when it slid off the table was approximately 4.43 m/s.