Sorry for re-posting but I need to know if I did it right, please help, I worked out the problem I just want to know if I did it right.

A shopper in a supermarket pushes a cart with a force of 35 N directed at an angle of 52(angle sign here) downward from the horizontal. Find the work done by the shopper on the cart as the shopper moves along a 50.0 m length of aisle.

Someone tell me if this is right:

W= (35.0N) (50.0m)(cos25.0)

W= 1586 J

If not please show me how to do it.

Yeah that is totally right!!!!

:D

I want to deal with the exercises on physic. plz help me.

To determine if you have the correct answer, let's go through the steps to solve the problem and check if you followed them correctly.

The work done on an object is given by the equation:
W = F * d * cos(theta)

Where:
W is the work done on the object,
F is the force applied on the object,
d is the distance the object is moved, and
theta is the angle between the force and the direction of motion.

In this case:
F = 35.0 N (the force applied by the shopper),
d = 50.0 m (the distance the shopper moves), and
theta = 52° (the angle between the force and the horizontal direction).

Now, plug the values into the formula:

W = (35.0 N) * (50.0 m) * cos(52°)

To evaluate this, you need to convert degrees to radians. The cosine function in most calculators assumes input in radians, so you need to use the conversion formula: radians = degrees * (π/180).

Using the conversion formula, the angle in radians is:
theta_radians = 52° * (π/180) ≈ 0.907 radians

Now you can substitute the angle in radians into the equation:

W = (35.0 N) * (50.0 m) * cos(0.907 radians)

Evaluating the cosine function, you get:

W ≈ (35.0 N) * (50.0 m) * 0.623

Calculating this expression, you get:

W ≈ 1087.25 J

Therefore, the correct answer is approximately 1087.25 Joules.

Based on your calculation, it seems that you made a mistake in the calculation of the cosine. You used cos(25°) instead of cos(52°). By correcting that, you should find the correct answer of approximately 1087.25 J.