For the reaction C3H8+5CO2=3CO2+4H2O
How many grams of O2 react with 8.80grams of C3H8? I think the ans is 32.0gO2
You really need to be more careful with yur typing. The reaction you have has CO2 on both sides. I'm sure you meant 5O2 on the left and not 5CO2. The same applies to your other posts, also.
I think the answer is 31.9 g O2 but the difference may be in what we used as the molar mass C3H8. I used 44.097. If I use 44 g for the molar mass C3H8 I get 32.0 also.
To determine the number of grams of O2 that react with 8.80 grams of C3H8, we can use stoichiometry.
First, we need to balance the chemical equation correctly:
C3H8 + 5O2 -> 3CO2 + 4H2O
The balanced equation tells us that 1 mole of C3H8 reacts with 5 moles of O2. Therefore, we can set up a stoichiometric ratio based on the molar mass of C3H8 and O2.
The molar mass of C3H8 (propane) is:
3 * 12.01 g/mol (atomic mass of carbon) + 8 * 1.01 g/mol (atomic mass of hydrogen) = 44.11 g/mol
Using this information, we can calculate the number of moles of C3H8, which is:
8.80 g C3H8 * (1 mol C3H8 / 44.11 g C3H8) = 0.1996 mol C3H8
Now, using the stoichiometric ratio, we can determine the number of moles of O2 required:
0.1996 mol C3H8 * (5 mol O2 / 1 mol C3H8) = 0.998 mol O2
Finally, to find the mass of O2 in grams, we can use the molar mass of O2, which is 32.00 g/mol:
0.998 mol O2 * (32.00 g O2 / 1 mol O2) = 31.94 g O2
Therefore, the correct answer is approximately 31.94 grams of O2.