What is the equation of the axis of symmetry of the graph with the order pairs of (-2,0) and (6,0).

How would I do this since? I thought perhaps I could do -2+__=6 which would be 8 then 8/2 =4 so x=4 my brother says I'm suppose to do 6-2=4/2=2 so x=2 who's right or are we both wrong.I've always been given an equation and then used -b/2a to find the vertex. I've searched and can't find any examples when given two x- intersects ordered pairs.

Half way between is x=2

To find the equation of the axis of symmetry, you need to determine the x-coordinate of the vertex, which is the midpoint between the x-values of the given points. Let's break down the steps to find the correct answer:

1. Find the x-coordinate of the midpoint: To do this, add the x-coordinates of the given points and divide by 2. In this case, it would be (-2 + 6) / 2 = 4 / 2 = 2. So the midpoint has an x-coordinate of 2.

2. Determine the equation of the axis of symmetry: The equation of the axis of symmetry is x = a, where 'a' is the x-coordinate of the midpoint. Therefore, in this case, the equation of the axis of symmetry is x = 2.

So, your brother was correct in using the formula (6 - 2) / 2 = 4 / 2 = 2 to find the x-coordinate of the midpoint and then deriving the equation x = 2. The approach you initially used of -2 + __ = 6 is not relevant for finding the equation of the axis of symmetry.

Note: The equation of the axis of symmetry is the vertical line that passes through the vertex of a parabola. When given two x-intercepts or any two points on the parabolic curve, determining the midpoint of their x-coordinates gives you the x-coordinate of the vertex.