strontium nitrate reacts with potassium iodate. What is its molecular,ionic and net ionic equations?
Sr(NO3)2 + 2KIO3 ==> Sr(IO3)2(s) + 2KNO3
Sr(IO3)2 is not all that insoluble (about 0.2 g/100 mL at room temperature) but I think for the purpose of this equation it is to be a solid. You should be able to take this information and turn the molecular into a net ionic eauation.
Oh, chemistry jokes! I'm always up for some molecular humor. Here's the scoop on the reaction between strontium nitrate (Sr(NO3)2) and potassium iodate (KIO3):
Molecular Equation: 2 Sr(NO3)2 + KIO3 → Sr(IO3)2 + 2 KNO3
Ionic Equation: 2 Sr^2+ + 4 NO3^- + 2 K+ + IO3^- → Sr(IO3)2 + 2 K+ + 4 NO3^-
Net Ionic Equation: 2 Sr^2+ + IO3^- → Sr(IO3)2
From nitrate ions to strontium cations, there's a whole lot of chemistry fun happening here. Enjoy, and don't forget to laugh in the face of any chemical reactions that come your way!
To determine the molecular, ionic, and net ionic equations for the reaction between strontium nitrate (Sr(NO3)2) and potassium iodate (KIO3), we need to consider the individual ions involved in the reaction.
The balanced chemical equation for the reaction can be written as:
Sr(NO3)2 + 2KIO3 → Sr(IO3)2 + 2KNO3
Now, we can break down this equation into its molecular, ionic, and net ionic forms:
1. Molecular equation:
Sr(NO3)2 + 2KIO3 → Sr(IO3)2 + 2KNO3
This equation represents the balanced reaction in terms of the overall compounds involved.
2. Ionic equation:
Taking into account the dissociation of the compounds into their constituent ions, we can rewrite the ionic equation as follows:
Sr2+(aq) + 2NO3-(aq) + 2K+(aq) + 2IO3-(aq) → Sr(IO3)2(s) + 2K+(aq) + 2NO3-(aq)
In this equation, the ions that are present in the solution are explicitly represented.
3. Net Ionic equation:
The net ionic equation is obtained by removing the spectator ions, which are ions that do not participate in the chemical reaction. In this case, the spectator ions are the 2K+(aq) and 2NO3-(aq) ions, which are present on both sides of the equation. Thus, we can cancel them out:
Sr2+(aq) + 2IO3-(aq) → Sr(IO3)2(s)
As a result, the net ionic equation for the reaction is:
Sr2+(aq) + 2IO3-(aq) → Sr(IO3)2(s)
This net ionic equation focuses only on the ions involved in the actual chemical transformation and excludes the spectator ions.
To determine the molecular, ionic, and net ionic equations, we need to first write the balanced chemical equation for the reaction between strontium nitrate (Sr(NO3)2) and potassium iodate (KIO3).
The chemical formulas for strontium nitrate and potassium iodate are Sr(NO3)2 and KIO3, respectively. Both compounds are soluble in water, so they will dissociate into their constituent ions when dissolved in water.
Balanced molecular equation:
Sr(NO3)2 + 2KIO3 → Sr(IO3)2 + 2KNO3
In the molecular equation, we represent the compounds and their states as written. However, it only gives us information about the reactants and products as a whole, not the individual ions involved.
To write the ionic equation, we need to show the dissociation of the soluble ionic compounds into their respective ions:
Sr(NO3)2 (aq) + 2KIO3 (aq) → Sr(IO3)2 (aq) + 2KNO3 (aq)
(The (aq) represents that the compound is dissolved in water.)
Ionic equation:
Sr^2+ (aq) + 2NO3- (aq) + 2K+ (aq) + 2IO3- (aq) → Sr(IO3)2 (s) + 2K+ (aq) + 2NO3- (aq)
The ionic equation shows the dissolved ions in solution, including spectator ions (ions that do not participate in the reaction). In this case, the potassium ions (K+) and nitrate ions (NO3-) are spectator ions because they appear on both sides of the equation.
Finally, to obtain the net ionic equation, we remove the spectator ions from the ionic equation:
Net ionic equation:
Sr^2+ (aq) + 2IO3- (aq) → Sr(IO3)2 (s)
The net ionic equation focuses on the species that actually participate in the reaction. It represents the essence of the reaction by including only the ions or molecules that undergo a change.
So, the molecular equation is Sr(NO3)2 + 2KIO3 → Sr(IO3)2 + 2KNO3, the ionic equation is Sr^2+ (aq) + 2IO3- (aq) → Sr(IO3)2 (s), and the net ionic equation is Sr^2+ (aq) + 2IO3- (aq) → Sr(IO3)2 (s).