A 0.130 kg baseball, traveling 35.0 m/s, strikes the catcher's mitt, which recoils 11.0 cm in bringing the ball to rest. What was the average force (in newtons) applied by the ball to the mitt?

i don't know it

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780 To find the average force applied by the ball to the mitt, you can use the principle of conservation of momentum. The initial momentum of the ball is equal to its final momentum when it comes to a stop.

The momentum of an object is given by the product of its mass and velocity. In this case, the initial momentum of the ball is:

Initial momentum = mass × velocity = 0.130 kg × 35.0 m/s

The final momentum of the ball is zero because it comes to rest. So we have:

Final momentum = 0 kg × 0 m/s = 0

According to the principle of conservation of momentum, the initial momentum of the ball is equal to the final momentum. Therefore:

0.130 kg × 35.0 m/s = 0

Now, we need to find the average force applied by the ball to the mitt. This force can be calculated using the formula:

Average force = Change in momentum / Time

Since the initial and final momenta are equal (both zero), the change in momentum is also zero. This means the average force is zero.