A person pulls a toboggan for a distance of 20.0 m along the snow with a rope directed 25.0° above the snow. The tension in the rope is 85.0 N.

(a) How much work is done on the toboggan by the tension force?

(b) How much work is done if the same tension is directed parallel to the snow?

I will be happy to check your work. Break the puling force into horizontal and vertical components.

work= forcehorizontal*distance.

To determine the amount of work done on the toboggan in both scenarios, we need to use the formula for work:

Work = Force * Displacement * cos(θ)

Where:
- Work represents the amount of work done on the object (in Joules).
- Force represents the applied force (in Newtons).
- Displacement represents the distance traveled by the object (in meters).
- θ represents the angle between the force and the displacement vectors (in degrees).

Let's calculate the work done in both scenarios:

(a) When the tension force is directed 25.0° above the snow:
- Force = 85.0 N (given)
- Displacement = 20.0 m (given)
- θ = 25.0° (given)

Work = 85.0 N * 20.0 m * cos(25.0°)
To calculate the cosine of 25.0°, we can use a scientific calculator or a mathematical software tool.
Work = 85.0 N * 20.0 m * 0.907
Work ≈ 1542 J

Therefore, the work done on the toboggan by the tension force when directed 25.0° above the snow is approximately 1542 Joules.

(b) When the tension force is directed parallel to the snow:
- Force = 85.0 N (given)
- Displacement = 20.0 m (given)
- θ = 0° (force is parallel to displacement)

Work = 85.0 N * 20.0 m * cos(0°)
Since the cosine of 0° is equal to 1,
Work = 85.0 N * 20.0 m * 1
Work = 85.0 N * 20.0 m
Work = 1700 J

Therefore, the work done on the toboggan by the tension force when directed parallel to the snow is 1700 Joules.