Find the volume of the solid obtained by rotating the region bounded by the given curves about the specified axis.

y=x^2, x=y^2, about the axis x=-5...
i just cant seemt to get the numbers to work out well and get answer please help...thanks

I see it as volume =

π[integral](y^(1/2) + 5)^2 dy - π[integral] (y^2+5)^2 dy
= π[integral](y + 10y^(1/2) + 25) dy - π[integral] (y^4 + 10y^2 + 25) dy both from 0 to 1
= π[(1/2)y^2 + (20/3)y^3 + 25y] form 0 to 1 - π[(1/5)y^5 + (10/3)y^3 + 25y] from 0 to 1
= π(1/2 + 20/3 + 25 - 0) - π(1/5 + 10/3 + 25 - 0)
= 109π/30

better check my arithmetic.