What is the molecular mass of: C19H97Cl35

I will be happy to critique your thinking, in this mythical formula.

ok so

C = 19x 12.01 = 228.19
H = 97 x 1.001 = 97.097
Cl = 35 x 35.45 = 1240.75
=1566.037 g/mol is this look ok

ok so

C = 19x 12.01 = 228.19
H = 97 x 1.001 = 97.097
Cl = 35 x 35.45 = 1240.75
=1566.82

1566.82 looks ok to me. Of course we realize this is a made up compound?

To calculate the molecular mass of C19H97Cl35, we need to first determine the atomic masses of the elements present (C, H, and Cl) and then sum up their contributions.

1. Look up the atomic masses of carbon (C), hydrogen (H), and chlorine (Cl) from a periodic table or an online resource. The atomic mass of carbon is approximately 12.01 grams per mole (g/mol), hydrogen is approximately 1.01 g/mol, and chlorine is approximately 35.45 g/mol.

2. Count the number of each element in the chemical formula. In C19H97Cl35, there are 19 carbon atoms (C), 97 hydrogen atoms (H), and 35 chlorine atoms (Cl).

3. Multiply the number of atoms of each element by its atomic mass. The molecular mass is the sum of these calculated values.

Let's perform the calculation:

Molecular mass = (19 * atomic mass of carbon) + (97 * atomic mass of hydrogen) + (35 * atomic mass of chlorine)

Substituting the atomic masses of the elements:

Molecular mass = (19 * 12.01 g/mol) + (97 * 1.01 g/mol) + (35 * 35.45 g/mol)

Calculating this expression:

Molecular mass = 228.19 g/mol + 97.97 g/mol + 1240.75 g/mol

Adding up the values:

Molecular mass = 1566.91 g/mol

Therefore, the molecular mass of C19H97Cl35 is approximately 1566.91 grams per mole.