A student weighs out 0.568 g of KHP (molar mass=204g/mol) and titrates to the equivalence point with (36.78 cm cubed which is 3) of a stock NaOH solution. What is concentration of stock NaOH solution? KHP is an acid with one acidic proton.

The word cubed is in word form because my computer does not have that symbol.

Thanks

You can do one or two things for that cubed symbol. You can write cm^3 (the caret means raised to the power in computer language), OR you can write the volume as cc. 36.78 cm^3 = 38.78 cubic centimeters = 38.78 cc. A cc = mL also.

mols KHP = grams/molar mass = ??
moles NaOH = same since KHP has one acidic proton and NaOH has one OH.
Then M NaOH = moles NaOH/L NaOH.

To find the concentration of the stock NaOH solution, we can use the formula:

Molarity (M) = (moles of solute) / (volume of solution in liters)

First, let's calculate the moles of KHP used in the titration:

Moles of KHP = Mass of KHP / Molar mass of KHP
Moles of KHP = 0.568 g / 204 g/mol
Moles of KHP = 0.00278 mol

Since KHP is a monoprotic acid, it reacts in a 1:1 ratio with NaOH. This means that the moles of NaOH used in the titration are also 0.00278 mol.

Next, we need to convert the volume of NaOH solution used in the titration to liters:

Volume of NaOH solution = 36.78 cm³ = 36.78 mL = 0.03678 L

Now, we can use the formula to find the concentration of the NaOH solution:

Molarity of NaOH = Moles of NaOH / Volume of NaOH solution
Molarity of NaOH = 0.00278 mol / 0.03678 L
Molarity of NaOH ≈ 0.0756 M

Therefore, the concentration of the stock NaOH solution is approximately 0.0756 M.

To find the concentration of the stock NaOH solution, we can set up a balanced chemical equation and use stoichiometry. The balanced equation for the reaction between KHP and NaOH is:

KHP + NaOH -> NaKP + H2O

From the balanced equation, we can see that one mole of KHP reacts with one mole of NaOH.

First, let's calculate the number of moles of KHP used in the reaction. We are given the mass of KHP as 0.568 g and the molar mass of KHP as 204 g/mol. We can use the formula:

Number of moles = Mass / Molar mass

Number of moles of KHP = 0.568 g / 204 g/mol = 0.0027843 mol

Since one mole of KHP reacts with one mole of NaOH, the number of moles of NaOH used in the reaction is also 0.0027843 mol.

Next, we need to determine the volume of the stock NaOH solution that reacts with the KHP. We are given the volume of NaOH solution as 36.78 cm³.

Now, we can calculate the concentration of the stock NaOH solution using the formula:

Concentration (in mol/cm³) = Number of moles / Volume (in cm³)

Concentration of NaOH solution = 0.0027843 mol / 36.78 cm³ = 0.00007573 mol/cm³

Therefore, the concentration of the stock NaOH solution is 0.00007573 mol/cm³.