How do find the speed of a marble after falling from rest a distance of 1.2 m?
To find the speed of a marble after falling from rest, we can use the equation for the final velocity of an object in free fall:
vf = √(2gh)
Where:
vf is the final velocity,
g is the acceleration due to gravity (approximately 9.81 m/s² on Earth),
and h is the height or distance the object has fallen.
In this case, the height, h, is 1.2 meters. We can substitute the values into the equation:
vf = √(2 * 9.81 * 1.2)
Now, we can calculate the final velocity, vf:
vf ≈ √(23.54)
vf ≈ 4.85 m/s
Therefore, the speed of the marble after falling from rest a distance of 1.2 meters is approximately 4.85 m/s.