A 112 mL solution of 0.351 M HCl is added to 52.0 mL of 0.161 M HCl. What is the new concentration of HCl?
M x L for soln 1.
M x L for soln 2.
M new soln = total moles/total L.
0.291 M
To find the new concentration of HCl after the two solutions are mixed, we need to calculate the total moles of HCl in both solutions and divide it by the total volume of the mixed solution.
Step 1: Calculate the moles of HCl in the first solution.
Given:
Volume of the first solution (V1) = 112 mL
Concentration of HCl in the first solution (C1) = 0.351 M
We can use the formula:
moles = concentration × volume
moles HCl in the first solution = C1 × V1
= 0.351 M × 0.112 L (since 1 mL = 0.001 L)
= 0.039312 mol
Step 2: Calculate the moles of HCl in the second solution.
Given:
Volume of the second solution (V2) = 52.0 mL
Concentration of HCl in the second solution (C2) = 0.161 M
moles HCl in the second solution = C2 × V2
= 0.161 M × 0.052 L
= 0.008372 mol
Step 3: Calculate the total moles of HCl in the mixed solution.
Total moles of HCl = moles from first solution + moles from second solution
= 0.039312 mol + 0.008372 mol
= 0.047684 mol
Step 4: Calculate the total volume of the mixed solution.
Total volume = volume of the first solution + volume of the second solution
= 112 mL + 52.0 mL
= 164 mL
Step 5: Calculate the new concentration of HCl.
New concentration = Total moles of HCl / Total volume
= 0.047684 mol / 0.164 L (since 1 mL = 0.001 L)
≈ 0.291 M
Therefore, the new concentration of HCl after mixing the two solutions is approximately 0.291 M.
To find the new concentration of HCl after the two solutions are mixed, we can use the concept of the conservation of moles of a substance.
First, we need to calculate the number of moles of HCl in each solution:
Number of moles = concentration (M) * volume (L)
For the first solution:
Number of moles of HCl in 112 mL = 0.351 M * 0.112 L
For the second solution:
Number of moles of HCl in 52 mL = 0.161 M * 0.052 L
Next, we need to determine the total number of moles of HCl in the mixed solution by summing the moles from both solutions:
Total moles of HCl = moles of HCl in first solution + moles of HCl in second solution
Now that we have the total moles, we can calculate the final concentration:
Final concentration = total moles of HCl / total volume (in liters)
Total volume = volume of the first solution + volume of the second solution
Let's plug in the values and calculate the answer.
Number of moles of HCl in the first solution:
0.351 M * 0.112 L = 0.039312 moles
Number of moles of HCl in the second solution:
0.161 M * 0.052 L = 0.008372 moles
Total moles of HCl = 0.039312 moles + 0.008372 moles = 0.047684 moles
Total volume = 112 mL + 52 mL = 164 mL = 0.164 L
Final concentration = 0.047684 moles / 0.164 L = 0.2917 M
Therefore, the new concentration of HCl is approximately 0.292 M.