find the x and y intercepts:
3x - 2y = -12
i know for the x intercept, put y=0 in the equation,s olve for x. For the y intercept, do the reverse. But i still don't understand how to solve it. Its just majorly fustrating me. And i can't go to school and ask a teacher because im suspended for 30 days and im not allowed on any CCPS property.
The y-intercept is where the line cuts the y-axis, therefore you put x=0 and solve for the value of y.
y=-12/-2=6 in this case.
The x-intercept is where the line cuts the x-axis, therefore, put y=0, and solve for x.
x=-12/3 = -4
If you need more explanations, post.
I'm sorry to hear about your situation. I'll be happy to help you understand how to find the x and y intercepts of the given equation.
To find the x-intercept, you're right that you need to set y = 0 in the equation and solve for x. Let me walk you through the process step by step.
Given: 3x - 2y = -12
1. Substitute y = 0 into the equation:
3x - 2(0) = -12
2. Simplify the equation:
3x = -12
3. Solve for x by isolating x:
Divide both sides of the equation by 3:
x = -12/3
x = -4
Therefore, the x-intercept is at (-4, 0), where the graph of the equation crosses the x-axis.
To find the y-intercept, you need to set x = 0 in the equation and solve for y. Again, let's go through the steps:
1. Substitute x = 0 into the equation:
3(0) - 2y = -12
2. Simplify the equation:
-2y = -12
3. Solve for y by isolating y:
Divide both sides of the equation by -2, remembering to flip the inequality sign:
y = -12/-2
y = 6
Therefore, the y-intercept is at (0, 6), where the graph of the equation crosses the y-axis.
I hope this explanation helps you understand how to find the x and y intercepts of a given equation. If you have any further questions, feel free to ask!