Determine the theoretical yield of CO2 if 250.0 g CaCO3 is heated.
one easy way is to figure the percentage of CO2 in CaCO3.
%= molmassCO2/molmassCaCO3
To determine the theoretical yield of CO2 when heating CaCO3, we need to use stoichiometry. The chemical equation for this reaction is:
CaCO3 (s) -> CaO (s) + CO2 (g)
To calculate the theoretical yield of CO2, we'll follow these steps:
1. Determine the molar mass of CaCO3: Ca = 40.08 g/mol, C = 12.01 g/mol, O = 16.00 g/mol.
Molar mass of CaCO3 = (40.08 g/mol × 1) + (12.01 g/mol × 1) + (16.00 g/mol × 3)
= 40.08 g/mol + 12.01 g/mol + 48.00 g/mol
= 100.09 g/mol
2. Convert the given mass of CaCO3 to moles using its molar mass:
Moles of CaCO3 = Mass of CaCO3 / Molar mass of CaCO3
= 250.0 g / 100.09 g/mol
= 2.499 moles (approximately)
3. Determine the mole ratio of CO2 to CaCO3 from the balanced chemical equation:
From the equation, the mole ratio of CO2 to CaCO3 is 1:1.
4. Theoretical yield of CO2 = Moles of CaCO3 × Mole ratio of CO2 to CaCO3
= 2.499 moles × 1
= 2.499 moles
5. Convert the number of moles of CO2 to grams using the molar mass of CO2:
Molar mass of CO2 = (12.01 g/mol × 1) + (16.00 g/mol × 2)
= 12.01 g/mol + 32.00 g/mol
= 44.01 g/mol
Grams of CO2 = Moles of CO2 × Molar mass of CO2
= 2.499 moles × 44.01 g/mol
= 110.00 g (rounded to two decimal places)
Therefore, the theoretical yield of CO2 is 110.00 grams.