A 4600 kg helicopter accelerates upward at 2.26 m/s2. 2
The acceleration of gravity is 9.8 m/s .
What lift force is exerted by the air on the propellers?
lift force=ma+mg
To find the lift force exerted by the air on the propellers, we need to calculate the net force acting on the helicopter.
First, let's calculate the weight of the helicopter, which is the force of gravity acting on it. The weight can be calculated using the formula:
Weight = mass * acceleration due to gravity
Given:
Mass of the helicopter (m) = 4600 kg
Acceleration due to gravity (g) = 9.8 m/s^2
Weight = 4600 kg * 9.8 m/s^2 = 45,080 N
Since the helicopter is accelerating upward, we need to take the direction into account. The net force acting on the helicopter is the sum of the weight (acting downward) and the lift force (acting upward). Therefore, we have:
Net force = Weight - Lift force
Since the helicopter is accelerating upward, the net force should be positive. So we have:
Net force = m * a
Given:
Mass of the helicopter (m) = 4600 kg
Acceleration of the helicopter (a) = 2.26 m/s^2
Net force = 4600 kg * 2.26 m/s^2 = 10,396 N
Now, we can calculate the lift force by rearranging the formula:
Lift force = Weight - Net force
Lift force = 45,080 N - 10,396 N = 34,684 N
Therefore, the lift force exerted by the air on the propellers is 34,684 Newtons.