A crate of mass m = 230 kg is pushed at constant speed up the frictionless ramp (θ = 29.0°) by a horizontal force F. What is the magnitude of F? What is the magnitude of the force exerted by the ramp on the crate?

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what the hell pls die i need answers why did you want me to answer this -_-

To find the magnitude of F, we need to analyze the forces acting on the crate. In this case, the only force acting parallel to the ramp is the force F, while the weight of the crate acts vertically downwards.

Let's start by finding the weight of the crate. The weight (W) is given by the formula:

W = m * g,

where m is the mass of the crate and g is the acceleration due to gravity.

In this case, the mass of the crate is 230 kg and the acceleration due to gravity is approximately 9.8 m/s^2. Therefore, the weight of the crate is:

W = 230 kg * 9.8 m/s^2
= 2254 N.

Since the crate is being pushed up the ramp at a constant speed, the force of gravity acting downwards must be balanced by the force F acting upwards.

Therefore, the magnitude of F is equal to the weight of the crate:

|F| = |W|
= 2254 N.

Now, let's find the magnitude of the force exerted by the ramp on the crate. This force is normal to the surface of the ramp, perpendicular to the weight of the crate.

To find this force, we'll use the formula:

force_normal = W * cos(θ),

where θ is the angle of the ramp. In this case, θ is 29.0°.

Substituting the values, we have:

force_normal = 2254 N * cos(29.0°)
= 2020 N.

Therefore, the magnitude of the force exerted by the ramp on the crate is 2020 N.