How many moles of silver are contained in 1.00kg of silver

1.00 kg(1000g/1 kg)(1 mol/ 108 g Ag) =

Answer
9.26 would this be correct or would it have like a 10 ^ ____ ????

If I use 107.87 for the atomic mass of Ag, I get 9.27 mols.

So it would just be 9.27 no 10^ power

The only reason for using a 10^ power notation is if we have too many digits at the end to locate the decimal point. In this case, the 1.00 kg is 3 significant figures and 9.27 is 3 s.f. so we don't need anything to locate the decimal point.

An example of using the scientific notation might be the following:
40*20 = 800 but we can have only two s.f. because both 40 and 20 have two s.f. If we put a decimal point at 800. that tells us the last zero is significant and it isn't since we have only two; therefore, we write 800 as 8.0 x 10^2. That tells us that the number is 800 but 8 and 0 are the only signifigant figures. I hope this helps.

To calculate the number of moles of silver in 1.00 kg of silver, you can use the formula:

n = m/M

Where:
n = number of moles
m = mass of the substance (in grams)
M = molar mass of the substance (in grams/mole)

In this case, the molar mass of silver (Ag) is approximately 108 g/mol.

Now let's calculate it step by step:

1. Convert kilograms to grams:
1.00 kg = 1000 g

2. Use the formula to calculate the number of moles:
n = (1000 g) / (108 g/mol) ≈ 9.26 mol

So, the correct answer is 9.26 moles of silver in 1.00 kg of silver. There is no need for any exponential notation (10^) in this case.