Math

A roofing crew can roof a house in 10 hours. If a second crew was added, the job would take 6 hours. How long would it take the second crew to roof the house alone?

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asked by Scott
  1. Working together is like resistors working in parallel:

    t1*t2 / (t1 + t2) = 6,
    10t2 / (10 + t2) = 6,
    Cross multiply:
    10t2 = 60 + 6t2,
    10t2 - 6t2 = 60,
    4t2 = 60,
    t2 = 60 / 4 = 15 h.

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    posted by Henry

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