A cubic box of volume 4.0 multiplied by 10-2 m3 is filled with air at atmospheric pressure at 20°C. The box is closed and heated to 160°C. What is the net force on each side of the box?

constant volume?

P1/P2=T1/T2 make certain temps are inkelvins.

force on each side= pressure/area. You will have to calculate the area of each side.

thats wrong bob it doesn't work.

To find the net force on each side of the box, we need to take into account the change in pressure inside the box as it is heated.

First, let's find the initial pressure of the air inside the box at 20°C. We can use the ideal gas law equation: PV = nRT.

Given:
Initial volume (V1) = 4.0 × 10^(-2) m³
Temperature at 20°C (T1) = 20 + 273 = 293 K
The number of moles (n) remains constant, so we can ignore it for this calculation.
The ideal gas constant (R) = 8.314 J/(mol·K)

Rearranging the ideal gas law equation, we can solve for the initial pressure (P1):
P1 = (nRT1) / V1

Since we can ignore the number of moles for this calculation, we can simplify further:
P1 = (RT1) / V1

Next, let's find the final pressure of the air inside the box at 160°C (T2 = 160 + 273 = 433 K). We will use the same equation as above, but with the final temperature (T2) instead:
P2 = (RT2) / V1

Now, let's calculate the net force on each side of the box. The net force can be found using the equation:
Net force = Pressure difference × Area

Given:
The box is cubic, so all sides have the same area.
Area of one side of the box (A) = side length × side length = (V1)^(1/3) × (V1)^(1/3)
The change in pressure (delta P) = P2 - P1

Now, substitute the values into the equation to find the net force:
Net force = (P2 - P1) × A

By following these steps and substituting the appropriate values, you can calculate the net force on each side of the box.