If three times the smaller of two consecutive integers is added to four times the larger, the result is 39. Find the smaller integer
consecutive integers --- x, x+1
3x + 4(x+1) = 39
3x + 4x + 4 = 39
7x = 35
x = 5
integers are 5 and 6
To solve this problem, let's assume the smaller integer is represented by x.
The larger integer would then be (x + 1) since it is consecutive.
According to the problem, three times the smaller integer plus four times the larger integer is equal to 39:
3x + 4(x + 1) = 39
Now, let's solve the equation step by step:
3x + 4x + 4 = 39
Combining like terms gives:
7x + 4 = 39
Subtracting 4 from both sides of the equation:
7x = 39 - 4
7x = 35
Finally, divide both sides of the equation by 7 to isolate x:
x = 35 / 7
Simplifying:
x = 5
Therefore, the smaller integer is 5.