Chemistry - College

The fuel value of hamburger is approx. 3.7 kcal/g. If a man eats 0.45 lbs of hamburger for lunch and none of the energy is stored in his body, estimate the amount of water that would have to be lost in perspiration to keep his body temperature constant. The heat of vaporization of water may be taken as 2.41 kJ/g. (1 lb = 453.6g)

Answer: ______ kg

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  1. Convert 0.45 # hamburger to grams
    0.45 lb x (453.6 g/lb)= ?? grams hamburger.
    ?? g hamburger x 3.71 kcal/g = xx kcal.
    I would convert that to kJoules.
    xx kcal x (4.184 kJ/kcal) = yy kJ.
    Then mass water x delta Hvap = yy kJ
    Solve for mass water. I get something a little over 1 kg.

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