What is the product of:

CH3COCH3 + Na+NH2- ?

Thanks from Sheryl

I can't help with this one. Sorry.

No problem! I'm here to help you. The product of CH3COCH3 + Na+NH2- can be determined by looking at the reaction between these two compounds.

CH3COCH3 is a ketone known as acetone, and Na+NH2- is a strong base called sodium amide. When a ketone reacts with a strong base, such as sodium amide, it undergoes a reaction called deprotonation.

Deprotonation involves the removal of a proton (H+) from the ketone molecule. In this case, the sodium amide acts as a base and abstracts a proton from the carbonyl carbon of acetone. After the deprotonation, the resulting product is an enolate anion.

So, the product of CH3COCH3 + Na+NH2- would be the deprotonated form of acetone, which is the enolate anion.