If 15.0 g of KCl is added to 100.0 g of water at 30.0 °C, how much more must be added to saturate the solution?
What's the solubility of KCl at 30.0 C?
it's 10?
You must have given me erroneous information. If the solubility of KCl at 30.0 C is 10 g/100 mL, then it is already saturated with 15 g.
Well, let's not "salty" about this! To determine how much more KCl needs to be added to saturate the solution, we need to find the solubility of KCl at this temperature. So, instead of pouring salt on the wound, let's get the answer!
At 30.0 °C, the solubility of KCl in water is approximately 34.2 g/100 g of water. Since you initially added 15.0 g of KCl, you need to add the difference between the amount already added and the solubility to reach saturation.
So, 34.2 g/100 g - 15.0 g = approximately 19.2 g.
It looks like you need to add approximately 19.2 grams more of KCl to fully saturate the solution. Just remember, it's always better to be "solution-oriented" rather than "dissolving" in a problem!
To find out how much more KCl needs to be added to saturate the solution, we need to determine the solubility of KCl in water at the given temperature. The solubility of a substance refers to the maximum amount of that substance that can dissolve in a given amount of solvent at a specific temperature.
Since the question doesn't provide specific solubility data, we can look up the solubility of KCl in water at 30.0 °C. The solubility of KCl in water at this temperature is approximately 34.2 g/100 mL.
Now, let's calculate the amount of KCl that has already been added to the solution. The question states that 15.0 g of KCl is added to 100.0 g of water. To convert the amount of water given in grams to milliliters, we need to use the density of water, which is approximately 1 g/mL. Therefore, 100.0 g of water is equal to 100.0 mL.
Next, we need to calculate the amount of KCl in the saturated solution. The solubility of KCl is 34.2 g/100 mL, so for every 100 mL of water, 34.2 g of KCl can dissolve. Since we have 100.0 mL of water in the solution, the amount of KCl that can dissolve is:
(34.2 g/100 mL) * 100.0 mL = 34.2 g
Since we have already added 15.0 g of KCl, the amount of KCl that needs to be added to saturate the solution is:
34.2 g - 15.0 g = 19.2 g
Therefore, you need to add 19.2 g more of KCl to saturate the solution at 30.0 °C.