h=2.4t+32.2
paul's height is 69.4 inches. What is the approximate length, in inches, of paul's tibia bone?
h=2.4t+32.2
69.4 = 2.4t + 32.2
69.4 - 32.2 = 2.4t
37.2 = 2.4t
37.2/2.4 = t
? = t
15.5
To find the approximate length of Paul's tibia bone, we need to substitute his height into the equation and solve for "t".
Given: h = 69.4 inches
Substituting the value of his height into the equation:
69.4 = 2.4t + 32.2
Now we can solve for "t" by isolating it on one side of the equation. First, subtract 32.2 from both sides:
69.4 - 32.2 = 2.4t
Simplifying the left side:
37.2 = 2.4t
To isolate "t", we need to divide both sides by 2.4:
37.2 / 2.4 = t
The approximate value of "t" is:
t ≈ 15.5
Therefore, to find the approximate length of Paul's tibia bone, we substitute the value of "t" back into the given equation:
h = 2.4t + 32.2
h = 2.4(15.5) + 32.2
h ≈ 108.2
The approximate length of Paul's tibia bone is 108.2 inches.
To find the approximate length of Paul's tibia bone, we need to solve the equation h = 2.4t + 32.2, where h represents the height in inches and t represents the length of the tibia bone.
First, let's substitute the given value for Paul's height into the equation:
69.4 = 2.4t + 32.2
To isolate the term with t, we need to move 32.2 to the other side of the equation by subtracting it from both sides:
69.4 - 32.2 = 2.4t
Next, we simplify the equation:
37.2 = 2.4t
To solve for t, we divide both sides of the equation by 2.4:
t = 37.2 / 2.4
Now, we can calculate the approximate length of Paul's tibia bone by dividing 37.2 by 2.4:
t ≈ 15.5
Therefore, the approximate length of Paul's tibia bone is approximately 15.5 inches.