if 125 ml of H2O is added to 50 ml of 0.35 M NaCl, what is the molarity of the resulting solution?

If the solutions are additive in volume,

0.35M x (50/175) = ??M

Well, if 125 ml of H2O is added to 50 ml of 0.35 M NaCl, you end up with a "salty water" solution. So, I would say the molarity of the resulting solution is "salty with a hint of hydration." Guess you can't escape the saltiness, even when you try to dilute it with water!

To find the molarity of the resulting solution, we need to combine the moles of water and NaCl.

Step 1: Calculate the amount of moles of NaCl.
Molarity (M) is defined as moles of solute per liter of solution.
Given:
Initial volume of NaCl solution (V NaCl) = 50 mL = 0.05 L
Molarity of NaCl solution (M NaCl) = 0.35 M

Moles of NaCl (n NaCl) = Molarity (M NaCl) x Volume (V NaCl)
= 0.35 M x 0.05 L
= 0.0175 moles

Step 2: Calculate the final volume of the solution.
Given:
Volume of water added (V H2O) = 125 mL = 0.125 L

Total volume of the resulting solution (V total) = Volume of NaCl solution (V NaCl) + Volume of water (V H2O)
= 0.05 L + 0.125 L
= 0.175 L

Step 3: Calculate the molarity of the resulting solution.
Molarity (M) is moles of solute per liter of solution.
Molarity of the resulting solution (M resulting) = Moles of solute (n NaCl) / Total volume of the solution (V total)

M resulting = 0.0175 moles / 0.175 L
≈ 0.1 M

Therefore, the molarity of the resulting solution is approximately 0.1 M.

To find the molarity of the resulting solution after adding 125 ml of water to 50 ml of 0.35 M NaCl, we need to consider the change in volume and the amount of solute.

First, let's calculate the final volume of the solution. When 125 ml of water is added to 50 ml of NaCl, the total volume becomes 125 ml + 50 ml = 175 ml.

Now, let's calculate the moles of NaCl in the original solution:

Moles of NaCl = Molarity × Volume (in liters)
= 0.35 M × 0.050 L (50 ml converted to liters)
= 0.0175 moles

Since the moles of NaCl remain the same even after adding water, we can find the new molarity of the solution by:

New Molarity = Moles of solute / Volume of solution (in liters)
= 0.0175 moles / 0.175 L (175 ml converted to liters)
≈ 0.1 M

Therefore, the molarity of the resulting solution is approximately 0.1 M.