suppose a 1-m(power3) sample of air at sea-level pressure, containing 4 g of water vapor, was cooled and condensation occurred. how many calories of heat would be released by this process?
q = mass water x heat fusion.
400
To calculate the number of calories of heat released by the condensation process, we need to know the heat of vaporization of water. The heat of vaporization is the amount of heat required to convert 1 gram of a substance from a liquid to a gas at its boiling point.
The heat of vaporization of water is approximately 540 calories per gram.
Given that there are 4 grams of water vapor condensed, we can calculate the total amount of heat released as follows:
Heat released = Heat of vaporization x Mass of water vapor
= 540 calories/gram x 4 grams
= 2160 calories
Therefore, approximately 2160 calories of heat would be released by this condensation process.