what is the osmolarity of a .20 M solution of Na3PO4?
It would be 0.2 x number of particles (which is 4; ie., 3 Na^+ and PO4^-3 ).
To calculate the osmolarity of a solution, you first need to know the number of particles that are present in solution. In this case, Na3PO4 will dissociate into 4 ions in solution (3 Na+ ions and 1 PO4^-3 ion). Therefore, the number of particles in solution is 4.
Next, you need to determine the concentration of the solution. The given concentration is 0.20 M, which means that there are 0.20 moles of Na3PO4 per liter of solution.
Finally, you can calculate the osmolarity using the following formula:
Osmolarity (osmol/L) = concentration (M) × number of particles
Substituting the values, we have:
Osmolarity = 0.20 M × 4 particles = 0.80 osmol/L
Therefore, the osmolarity of a 0.20 M solution of Na3PO4 is 0.80 osmol/L.