a marble that is rolling across a lab table has a velocity of 0.7m/s. If the table is 0.9m high, how far from the edge of the table will the ball travel in the horizontel direction before it hits the floor ?
find time of fall:
h= 1/2 g t^2 solve for t.
then distance= horizontal velocity*timeinair
i don't get it
To determine how far from the edge of the table the marble will travel in the horizontal direction before hitting the floor, we can use the equations of motion.
Step 1: First, let's find the time it takes for the marble to hit the ground. We can use the equation:
h = (1/2) * g * t^2
where h is the height of the table, g is the acceleration due to gravity (approximately 9.8 m/s^2), and t is the time taken. Rearranging this equation to solve for t, we get:
t = sqrt(2h / g)
Plugging in the values:
h = 0.9 m
g = 9.8 m/s^2
t = sqrt(2 * 0.9 / 9.8)
t = sqrt(0.1837)
t = 0.43 seconds (approx.)
Step 2: Next, let's determine the horizontal distance traveled by the marble during this time. We can use the equation:
d = v * t
where d is the horizontal distance traveled, v is the velocity of the marble (0.7 m/s), and t is the time.
Plugging in the values:
v = 0.7 m/s
t = 0.43 s (from Step 1)
d = 0.7 * 0.43
d ≈ 0.301 m
Therefore, the marble will travel approximately 0.301 meters from the edge of the table before it hits the floor in the horizontal direction.