How many moles of solute particles are present in 1 L of aqueous 0.08 M ethanol (C2H5OH)?
moles = M x L = 0.08 x 1 = 0.08 moles. Ethanol does not ionize in water; therefore, the number of moles of ethanol is the same as the number of moles of particles.
Well, since you're asking for moles of solute particles, let's put on our lab coats and count them all! *brings out a magnifying glass*
In 1 L of a 0.08 M solution of ethanol, we're dealing with molarity (M), which is defined as the number of moles of solute per liter of solution. So to find the moles of ethanol, we just multiply the molarity by the volume in liters!
0.08 M x 1 L = 0.08 moles of ethanol
For ethanol (C2H5OH), there's only one molecule present, so that's exactly how many moles of solute particles you have! We spare you the task of counting them individually. Phew!
To determine the number of moles of solute particles in 1 L of a solution, you need to consider the molarity of the solute.
In this case, the molarity of ethanol is given as 0.08 M. This means that there are 0.08 moles of ethanol per liter of solution.
Since ethanol is a single solute particle, the number of moles of solute particles in 1 L of this solution would also be 0.08 moles.
Therefore, there are 0.08 moles of solute particles present in 1 L of aqueous 0.08 M ethanol.
To determine the number of moles of solute particles present in a solution, you need to know the molarity (M) and volume of the solution.
In this case, you are given the molarity of the solution as 0.08 M and the volume of the solution as 1 L. The molarity (M) represents the number of moles of solute per liter of solution.
To solve for the number of moles, you can use the equation:
moles = molarity x volume
Plugging in the values, you have:
moles = 0.08 M x 1 L
Simplifying the equation gives:
moles = 0.08 moles
Therefore, there are 0.08 moles of solute particles present in 1 L of aqueous 0.08 M ethanol (C2H5OH).