Cl2 + 2koh-->kcl _kclo +H2O
3KClo-->2Kcl+kclo3
4kclo3-->3kclo4 +kcl
what mass of cl2 (g) is required to make 234g kclo4
This is a stoichiometry problem. I have posted an example problem. Just follow the steps.
http://www.jiskha.com/science/chemistry/stoichiometry.html
To find out the mass of Cl2 required to make 234g KClO4, we need to use the stoichiometry of the balanced chemical equations you provided.
Let's start with the first equation:
Cl2 + 2KOH → KCl + KClO + H2O
From this equation, we can see that the molar ratio between Cl2 and KClO is 1:1. This means that for every 1 mole of Cl2, we get 1 mole of KClO.
Next, let's move on to the second equation:
3KClO → 2KCl + KClO3
From this equation, we can see that the molar ratio between KClO and KClO3 is 3:1. This means that for every 3 moles of KClO, we get 1 mole of KClO3.
Finally, let's look at the third equation:
4KClO3 → 3KClO4 + KCl
From this equation, we can see that the molar ratio between KClO3 and KClO4 is 3:4. This means that for every 3 moles of KClO3, we get 4 moles of KClO4.
Now, let's calculate the molar mass of KClO4:
KClO4 = 39.10 g/mol (K) + 35.45 g/mol (Cl) + 16.00 g/mol (O) * 4 = 138.55 g/mol
To find the mass of Cl2 required to produce 234g of KClO4, we can use the following steps:
1. Calculate the number of moles of KClO4 using its molar mass:
Number of moles = mass / molar mass = 234g / 138.55 g/mol = 1.687 moles
2. Since the molar ratio between KClO3 and KClO4 is 3:4, we can calculate the number of moles of KClO3 produced:
Number of moles of KClO3 = (4 moles KClO4 / 3 moles KClO3) * 1.687 moles = 2.249 moles
3. Since the molar ratio between KClO and KClO3 is 3:1, we can calculate the number of moles of KClO produced:
Number of moles of KClO = (1 mole KClO3 / 3 moles KClO) * 2.249 moles = 0.7497 moles
4. Finally, since the molar ratio between Cl2 and KClO is 1:1, we can calculate the number of moles of Cl2 required:
Number of moles of Cl2 = 0.7497 moles
To convert the number of moles of Cl2 into grams, we can use its molar mass:
Molar mass = 2 * (Molar mass of Cl) = 2 * (35.45 g/mol) = 70.90 g/mol
Mass of Cl2 = number of moles * molar mass = 0.7497 moles * 70.90 g/mol = 53.19 g
Therefore, the mass of Cl2 required to make 234g of KClO4 is approximately 53.19 grams.