An automobile antifreeze mixture is made by mixing equal volumes of ethylene glycol (d=1.114 g/mL; M=62.07 g/mL) and water (d=1.00 g/mL) at 20 degrees C. The density of the mixture is 1.070 g/mL. Expreess the concentration of ethylene glycol as volume percent. I've tried this a couple times but keep getting it wrong if u could tell me step by step i'd really appreciate it
All the Quetions can be :
a-Volume percent ?
b-Mass percent ?
c-molarity ?
d-molality ?
e-mole fraction ?
answers:
assume 10 mL of ethylene glycol and 10 mL of water
mass ethylene glycol = 10 mL x 1.114 g/mL = 11.14 g
mass water = 10 mL x 1.00 g/mL = 10.0 g
mass solution = 11.14 + 10.0= 21.14 g
mass percent = 11.14 x 100/ 21.14 = 52.7
volume solution = 21.14 g / 1.070 g/mL=19.8 mL
volume percent = 10 x 100/ 19.8=50.5
moles ethylene glycol = 11.14 / 62.07 =0.179
M = 0.179/ 0.0198 L=9.06
m = 0.179/ 0.010 Kg = 17.9
moles water = 10.0 g/ 18.02 g/mol=0.555
mole fraction = 0.179/0.179 + 0.555 =0.244
I tried this.
Assume we mix 50.00 mL EG with 50.00 mL H2O.
mass EG = VD = 50.00 mL x 1.114 g/mL = 55.70 grams
mass H2O = VD = 50.00 mL x 1.00 g/mL = 50.00 grams.
Total mass = 55.70 + 50.00 = 105.70 grams.
V of total = m/d = 105.70/1.070 = 98.785 mL.
Then % v/v = 50.00 mL/98.785 mL = 50.61% EG
Well, mixing liquids can be a slippery situation, but don't worry, I'm here to help! To find the concentration of ethylene glycol as a volume percent, we'll need to follow a few steps.
Step 1: Calculate the mass of water (m_water) and ethylene glycol (m_ethylene glycol) in the mixture.
We know that the density of the mixture is 1.070 g/mL, so for a volume of 1 mL, the mixture would have a mass of 1.070 g.
Since we're mixing equal volumes of both liquids, that means we would have 0.5 mL of water and 0.5 mL of ethylene glycol in our mixture.
The mass of water can be calculated as follows:
m_water = density_water * volume_water = 1.00 g/mL * 0.5 mL = 0.50 g
The mass of ethylene glycol can be calculated as follows:
m_ethylene glycol = density_ethylene glycol * volume_ethylene glycol = 1.114 g/mL * 0.5 mL = 0.557 g
Step 2: Calculate the total mass of the mixture (m_total) by adding the mass of water and ethylene glycol.
m_total = m_water + m_ethylene glycol = 0.50 g + 0.557 g = 1.057 g
Step 3: Calculate the volume percent of ethylene glycol.
Volume percent = (volume_ethylene glycol / volume_total) * 100
Since we mixed equal volumes of ethylene glycol and water, the volume of ethylene glycol is 0.5 mL and the volume of the total mixture is 1 mL.
Volume percent = (0.5 mL / 1 mL) * 100 = 50%
So, the concentration of ethylene glycol in this mixture is 50% volume percent.
Hope that clears things up!
To express the concentration of ethylene glycol as volume percent, you need to determine the volume of ethylene glycol in the mixture and calculate the percentage it represents.
Here are the steps to solve this problem:
Step 1: Calculate the masses of ethylene glycol and water:
Given,
Density of ethylene glycol (ρ1) = 1.114 g/mL
Density of water (ρ2) = 1.00 g/mL
Since the volumes of ethylene glycol and water are equal in this mixture, we can assume that 1 mL of ethylene glycol and 1 mL of water are mixed.
Mass of ethylene glycol (m1) = volume × density = 1 mL × 1.114 g/mL = 1.114 g
Mass of water (m2) = volume × density = 1 mL × 1.00 g/mL = 1.00 g
Step 2: Calculate the total mass of the mixture:
Given,
Density of the mixture (ρ) = 1.070 g/mL
Let's assume the total volume of the mixture as 1 mL.
Then, the total mass of the mixture (m_total) = volume × density = 1 mL × 1.070 g/mL = 1.070 g
Step 3: Calculate the volume percent of ethylene glycol:
Volume percent is the ratio of the volume of ethylene glycol to the total volume of the mixture, multiplied by 100.
To find the volume of ethylene glycol, we need to convert the mass of ethylene glycol to its volume using its density.
Volume of ethylene glycol (V1) = m1 ÷ ρ1 = 1.114 g ÷ 1.114 g/mL = 1 mL
Volume percent of ethylene glycol = (V1 ÷ Volume of mixture) × 100
= (1 mL ÷ 1 mL) × 100
= 100%
Therefore, the concentration of ethylene glycol as volume percent is 100%.