Please help! Need to find the 6th and nth terms in this sequence - and solve for the rule or process.
here's the sequence:
1,3,9,27,81
What is the process or formula to get the nth term in the sequence.
Thanks!
You are multiplying the previous number by 3.
Numebers is previous number multiplied with 3
6th term 81*3=243
nth term
an=a*r^(n-1) Remark: a=1 , r=3
an=1*3^(n-1)
an=3^(n-1)
To find the pattern or rule for this sequence, we can observe that each number is obtained by multiplying the previous number by 3.
Starting with the first number 1, we multiply it by 3 to get 3.
Then, we multiply 3 by 3 to get 9.
Continuing this pattern, we multiply 9 by 3 to get 27, and so on.
So, the rule for this sequence is to multiply each term by 3 to get the next term.
To find the 6th term, we can apply this rule:
First term = 1
Second term = 1 * 3 = 3
Third term = 3 * 3 = 9
Fourth term = 9 * 3 = 27
Fifth term = 27 * 3 = 81
Sixth term = 81 * 3 = 243
Therefore, the 6th term in the sequence is 243.
To find the nth term in the sequence, we can use the general formula:
nth term = a * r^(n - 1)
where a is the first term, r is the common ratio (in this case, 3), and n is the position of the term we want to find.
For this sequence, the first term a = 1, and r = 3.
So, the formula becomes:
nth term = 1 * 3^(n - 1)
You can plug in any value of n to get the corresponding term in the sequence.