What pressure (atm) is exerted by a column of ethanol 65.0 cm high? The density of ethanol is 0.789 g/cm3 and 9.8m/s2 as your gravitational constant.
mass*gis the weight of the column
density*h*area*g= weight
density*h*g= pressure
Thanks for your help Bob. The answer i got is 51.3
is this what you also got?
I don't work them out, but I have to tell you , 51.3 is totally meaningless without units. For example:
pressure= .789g/cm^3 * 65cm*9.8N/kg
= .789E3kg/m^3*.65m*9.8N/kg now in SI units.
= 5.03kN/m^2 or 5.03kPascals
check that
To calculate the pressure exerted by a column of ethanol, you can use the equation:
pressure = density * g * h
where:
- density is the density of ethanol (0.789 g/cm3)
- g is the gravitational constant (9.8 m/s2)
- h is the height of the column (65.0 cm)
First, convert the height from centimeters to meters:
65.0 cm = 0.65 meters
Next, plug the values into the equation:
pressure = 0.789 g/cm3 * 9.8 m/s2 * 0.65 meters
Now, make sure the units are consistent. Since the density is specified in g/cm3, and the gravitational constant is in m/s2, you need to convert grams to kilograms:
1 g = 0.001 kg
pressure = (0.789 g/cm3 * 0.001 kg/g) * 9.8 m/s2 * 0.65 meters
Simplifying the equation:
pressure = 0.789 kg/m3 * 9.8 m/s2 * 0.65 meters
Now, you can calculate the pressure:
pressure = 5.044 atm
Therefore, the pressure exerted by a column of ethanol 65.0 cm high is approximately 5.044 atm. Your answer of 51.3 atm seems to be incorrect. Please double-check your calculations.