How much work must you do to push a 10 kg block of steel across a steel table friction is 0.6 at a steady speed of 1.3 m/s for 9.8 s?
do you mean the coefficent of sliding friction is .6?
at steady speed, 1.3m/s, figure how far the block goes (distance) in 9.8s
work= forcefriction*distance=mu*mg*distance
To calculate the work done to push the block across the table, we need to use the formula:
Work = Force x Distance
Where:
- Force is the force applied to overcome friction
- Distance is the distance traveled by the block
First, let's calculate the force of friction:
Force of friction = Friction coefficient x Normal force
The normal force is equal to the weight of the block, which is given by:
Weight = mass x gravity
Given:
- Mass of the block = 10 kg
- Gravity = 9.8 m/s²
Weight = 10 kg x 9.8 m/s² = 98 N
Now, let's calculate the force of friction:
Force of friction = 0.6 x 98 N = 58.8 N
Since the block is moving at a steady speed, the net force applied is zero. This means that the force applied to push the block is equal in magnitude but opposite in direction to the force of friction. Therefore, the force applied is 58.8 N.
To calculate the distance traveled, we use the formula:
Distance = Speed x Time
Given:
- Speed = 1.3 m/s
- Time = 9.8 s
Distance = 1.3 m/s x 9.8 s = 12.74 m
Finally, we can calculate the work done:
Work = Force x Distance = 58.8 N x 12.74 m = 749.35 J
Therefore, the work done to push the 10 kg block of steel across the steel table at a steady speed of 1.3 m/s for 9.8 s is 749.35 Joules.
To find the work done in pushing the block across the table, you need to calculate the product of the force required to overcome friction and the displacement of the block. The formula for work is:
Work = Force * Displacement * cos(theta)
However, since the block is moving at a steady speed, we can determine that the force applied is equal in magnitude and opposite in direction to the force of friction. Therefore, we can rewrite the equation as:
Work = (Force of Friction) * Displacement * cos(theta)
First, let's find the force of friction using the coefficient of friction and the normal force. The normal force is equal to the weight of the block, which is given by:
Normal Force = mass * gravity
Normal Force = 10 kg * 9.8 m/s^2
Normal Force = 98 N
The force of friction can be found using the formula:
Force of Friction = coefficient of friction * Normal Force
Force of Friction = 0.6 * 98 N
Force of Friction = 58.8 N
The angle theta between the displacement and force of friction is 0 degrees since they are in the same direction.
Now, we can calculate the work done:
Work = 58.8 N * Displacement * cos(0 degrees)
Work = 58.8 N * Displacement * 1
Finally, we need to find the displacement. Since the block is moving at a steady speed, the displacement is equal to the product of the speed and time:
Displacement = Speed * Time
Displacement = 1.3 m/s * 9.8 s
Displacement = 12.74 m
Now we can calculate the work:
Work = 58.8 N * 12.74 m
Work = 749.35 Joules
Therefore, the work done to push the 10 kg block across the steel table at a steady speed of 1.3 m/s for 9.8 s is 749.35 Joules.