Physics

6 J of work is needed to push an object of mass 2 kg from point A to point B of the frictionless inclined plane. If the angle of inclination is 30°, the height of the plane is h, what is the length s of the inclined plane?

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  1. The weight is M g = 19.6 N

    (Weight)* h = 6 J = work done
    Solve for the elevation change, h.
    That and the inclination angle will tell you the length s.

    h/s = sin 30.

    Get it?

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  2. Yes. Thank You!

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