What volume (in Liters) of hydrogen must react to form 17.0L of ammonia according to the following balanced equation:
N2(g) + 3H2(g) --> 2NH3(g)
Ratio from equation is H : NH3 = 3 : 2 = 3/2 : 1 = 17x3/2 : 17 = 25.5 : 17
17 L of hydrogen
can you check my work is this right?
Is what right. In my class I wouldn't give you credit ALTHOUGH the correct number is in there. It's just mixed up with a bunch of other numbers.
How in the world do you multiply 17 x 3/2 and get 17? The answer is 17 x 3/2 = 25.5 L which you had in your garbled math but the way you've presented it makes the answer unclear.
research chemistry
To determine the volume (in liters) of hydrogen needed to form 17.0L of ammonia according to the given balanced equation, you can use the stoichiometric ratio provided in the equation.
The stoichiometric ratio between hydrogen (H2) and ammonia (NH3) is 3:2, which means that for every 3 moles of hydrogen, 2 moles of ammonia are produced.
First, convert the given volume of ammonia (17.0L) to moles using the ideal gas law equation:
PV = nRT,
where P is the pressure (assuming constant and not given in this case),
V is the volume (17.0L),
n is the number of moles (unknown),
R is the ideal gas constant (0.0821 L·atm/(mol·K)),
and T is the temperature (assuming constant and not given in this case).
Using the equation rearranged to solve for n:
n = PV / RT.
Plug in the values:
n = (17.0L)(unknown)/(0.0821 L·atm/(mol·K))(unknown).
Next, using the stoichiometric ratio from the balanced equation:
3 moles of hydrogen : 2 moles of ammonia,
you can set up a proportion to find the moles of hydrogen needed:
(unknown moles of hydrogen) / (2 moles of ammonia) = (n moles of ammonia) / (1 mole of hydrogen).
Now, solve for the unknown moles of hydrogen:
unknown moles of hydrogen = (2 moles of ammonia)(unknown moles of hydrogen)/(1 mole of hydrogen).
Finally, convert the moles of hydrogen to volume (in liters) using the ideal gas law equation:
V = nRT / P.
Plug in the values:
V = (unknown moles of hydrogen)(0.0821 L·atm/(mol·K))(unknown)/(unknown).
After performing these calculations, you will determine the volume of hydrogen in liters needed to react and form 17.0L of ammonia.