The four tires of an automobile are inflated to a gauge pressure of 2.0x10^5 Pa. Each tire has an area of 0.024m^2 in contact with the ground. Determine the weight of the automobile.
Weight=pressuretire*area (all four tires)
so i do 2.0x10^5Pa x (0.024m^2)(4)??
would the answer be 19200?
An electric motor turns a flywheel through a drive belt that joins a pulley on the motor and a pulley that is rigidly attached to the flywheel as shown in the figure below. The flywheel is a solid disk with a mass of 55.5 kg and a radius R = 0.625 m. It turns on a frictionless axle. Its pulley has much smaller mass and a radius of 0.230 m. The tension Tu in the upper (taut) segment of the belt is 149 N, and the flywheel has a clockwise angular acceleration of 1.67 rad/s2. Find the tension in the lower (slack) segment of the belt.
To determine the weight of the automobile, we need to use the concept of pressure and area.
1. Start by calculating the force exerted by each tire on the ground.
- The pressure is given as 2.0x10^5 Pa, which represents the force per unit area.
- The area of each tire in contact with the ground is given as 0.024 m^2.
2. Use the formula: Force = Pressure x Area
- Force = (2.0x10^5 Pa) x (0.024 m^2)
3. Calculate the force exerted by one tire on the ground.
Force = 4.8x10^3 N (Newton)
4. Since each tire exerts the same force, multiply the force by 4 to account for all four tires.
Total force exerted by all four tires = (4.8x10^3 N) x 4
5. Calculate the weight of the automobile using the formula: Weight = Force
- The weight of an object is the force of gravity acting on it.
Weight of the automobile = (4.8x10^3 N) x 4
6. Calculate the weight of the automobile.
Weight of the automobile = 1.92x10^4 N (Newton)