A 4.3 kg bucket of water is raised from a well
by a rope.
The acceleration of gravity is 9.8 m/s2 .
If the upward acceleration of the bucket is
4.6 m/s2, find the force exerted by the rope
on the bucket.
Answer in units of N.
I'm almost sure the answer requires me to use Fnet= F1 + F2 = ma. I still haven't figured out exactly how to do this...I keep getting the wrong answer.
please don't post the same question multliple times
To solve this problem, you can use Newton's second law of motion, which states that the net force acting on an object is equal to its mass multiplied by its acceleration. In this case, the net force exerted on the bucket is given by the difference between the force exerted by gravity (downward) and the force exerted by the rope (upward).
Let's break down the problem step by step:
1. Calculate the force due to gravity acting on the bucket:
The force due to gravity is given by the formula F_gravity = m * g, where m is the mass of the bucket and g is the acceleration due to gravity. Plugging in the values we have:
F_gravity = 4.3 kg * 9.8 m/s^2
2. Calculate the net force on the bucket:
The net force acting on the bucket is equal to its mass multiplied by the upward acceleration minus the force due to gravity. Using the formula F_net = m * (a_upward - g):
F_net = 4.3 kg * (4.6 m/s^2 - 9.8 m/s^2)
3. Calculate the force exerted by the rope on the bucket:
The force exerted by the rope on the bucket is equal to the net force, as they are in opposite directions. So the force exerted by the rope is: F_rope = F_net
Now, you can plug in the values and calculate the final answer:
F_gravity = 4.3 kg * 9.8 m/s^2
F_net = 4.3 kg * (4.6 m/s^2 - 9.8 m/s^2)
F_rope = F_net
Performing the calculations should give you the answer in units of Newtons (N), which represents the force exerted by the rope on the bucket.