calculate the theoretical amount of CaCl2 that would be required to change the temperature of 50ml of water from room temperature 20C to 45C? Remember heat loss during the dissolution is equal to the heat capacity of water. this value is 4.184. you assume that the density of the water is 1g/ml.
To calculate the theoretical amount of CaCl2 required to change the temperature of 50 mL of water from 20°C to 45°C, we need to consider the heat transfer that occurs during the dissolution of CaCl2.
Firstly, let's calculate the heat energy required to increase the temperature of 50 mL of water from 20°C to 45°C. This can be done using the formula:
Q = m * C * ΔT,
where Q is the heat energy, m is the mass of the water, C is the heat capacity of water, and ΔT is the change in temperature.
From the information given, we know that the density of water is 1 g/mL. Therefore, the mass of 50 mL of water is:
mass = volume * density = 50 mL * 1 g/mL = 50 g.
The change in temperature, ΔT, is 45°C - 20°C = 25°C.
Now, substitute the values into the formula:
Q = 50 g * 4.184 J/g°C * 25°C
Q = 5230 J.
Next, we need to calculate the heat of dissolution, which is equal to the heat loss during the dissolution of CaCl2. The heat of dissolution is given as the heat capacity of water, which is 4.184 J/g°C.
Now, divide the heat energy required by the heat of dissolution to find the theoretical amount of CaCl2 required:
theoretical amount = Q / heat of dissolution
theoretical amount = 5230 J / 4.184 J/g°C
theoretical amount ≈ 1250 g.
Therefore, the theoretical amount of CaCl2 required to change the temperature of 50 mL of water from 20°C to 45°C is approximately 1250 grams.