Fred begins walking toward John house at 3 mi/h. John leaves his house at the same time and walks toward Fred's house on the same path at a rate of 2 mi/h. How long will it be before they meet if the distance between the houses is 4 miles?
First, I set up an equation, 3h+2h=4. I divided 4 by 5. So, I got h=4/5. Is this right?
yes
To find out how long it will take for Fred and John to meet, we need to first determine the total distance they will each cover before they meet.
Let's assume the time they both walk is "t" hours.
Fred's speed is 3 miles per hour, so in "t" hours, he will cover a distance of 3t miles.
John's speed is 2 miles per hour, so in "t" hours, he will cover a distance of 2t miles.
The total distance Fred and John cover must equal the distance between their houses, which is given as 4 miles.
So, we can set up the equation:
3t + 2t = 4
Combining like terms, we have:
5t = 4
Now, to solve for "t", divide both sides of the equation by 5:
t = 4/5
Therefore, your answer is correct. It will take Fred and John 4/5 hours to meet.