What is the balanced equation for the reaction of 3.000 g of K2CO3 and HCl?
To determine the balanced equation for the reaction between K2CO3 and HCl, we first need to understand the reactants and products involved.
K2CO3 represents potassium carbonate, which consists of potassium ions (K+) and carbonate ions (CO3^2-). HCl represents hydrochloric acid, which dissociates into hydrogen ions (H+) and chloride ions (Cl-).
The reaction between K2CO3 and HCl can be understood as an acid-base reaction, where the hydrogen ions from HCl react with the carbonate ions from K2CO3 to form water (H2O) and carbon dioxide (CO2).
The balanced equation for this reaction can be determined step-by-step:
1. Write the unbalanced equation:
K2CO3 + HCl -> H2O + CO2
2. Calculate the molar mass of K2CO3:
K2CO3 = 2(39.10 g/mol K) + 12.01 g/mol C + 3(16.00 g/mol O) = 138.21 g/mol
3. Determine the number of moles of K2CO3:
moles of K2CO3 = mass of K2CO3 / molar mass of K2CO3
moles of K2CO3 = 3.000 g / 138.21 g/mol = 0.0217 mol
4. Now, let's balance the equation by adjusting the coefficients:
K2CO3 + 2HCl -> 2H2O + CO2
5. The balanced equation is:
0.0217 mol K2CO3 + 2 mol HCl -> 2 mol H2O + 1 mol CO2
Therefore, the balanced equation for the reaction between 3.000 g of K2CO3 and HCl is:
K2CO3 + 2HCl -> 2H2O + CO2