how would you factor this expresssion I'm so confused. Thank you
x^3-4x^2+3x/x+2 times (x^2-3x)
looks simple enough...
(x^3-4x^2+3x)/(x+2)*(x^2-3x) , notice you need brackets
= x(x^2 - 4x + 3)/(x+2) * x(x-3)
= x(x-1)(x-3)/(x+2) * x(x-3)
even though it factored nicely, nothing can be done with it.
I am sure that you either typed it wrong, or it is a silly question.
HI monica that is this sign ^ i can help with.
To factor the expression (x^3 - 4x^2 + 3x)/(x + 2) * (x^2 - 3x), we can break it down into smaller components and factor each part separately. Let's start by simplifying the numerator of the first fraction.
The numerator (x^3 - 4x^2 + 3x) can be factored by finding the greatest common factor (GCF) of the terms and factoring it out. In this case, the GCF is x, so we rewrite the expression as x * (x^2 - 4x + 3x). Next, we can factor the quadratic expression x^2 - 4x + 3x.
To factor x^2 - 4x + 3x, we look for two numbers that add up to -4 and multiply to 3. The numbers that satisfy this condition are -1 and -3. Using these numbers, we can rewrite the expression as x * (x - 1)(x - 3).
Now, let's move on to the second part of the expression, (x^2 - 3x). This quadratic expression can be factored by finding the greatest common factor (GCF), which is x in this case. So we rewrite it as x(x - 3).
Combining the two parts, we have x * (x - 1)(x - 3) / (x + 2) * x(x - 3).
Now, we can look for common factors that can be simplified further. We observe that both (x - 3) and x are common terms in the numerator and denominator. Thus, we can cancel them out, which leaves us with the factored expression:
(x - 1) / (x + 2)
Therefore, the factored form of the original expression is (x - 1) / (x + 2).