if cosA is 5/13 and tangent Ais 5/12 how do i find the sine
cosA = adj/hyp
tanA = opp/adj
sinA = opp/hyp
To find the sine of angle A, you can use the Pythagorean identity for right triangles:
sin^2(A) + cos^2(A) = 1
Given that cos(A) = 5/13, we can substitute this value into the equation:
sin^2(A) + (5/13)^2 = 1
Let's solve for sin(A):
sin^2(A) = 1 - (5/13)^2
sin^2(A) = 1 - 25/169
sin^2(A) = 169/169 - 25/169
sin^2(A) = 144/169
Taking the square root on both sides:
sin(A) = √(144/169)
sin(A) = 12/13
So, the sine of angle A is 12/13.